2. In Arrhenius equation for a certain reaction,
the values of A and E, (activation energy) are
4 x 10 sec-1 and 98,6 KJ mol-1
respectively,
The specific rate constant is 1.1 x 10-3 s -1then
temperature is
Answers
Answered by
1
Answer:
According to Arrhenius equation,
k=Ae
−E
a
/RT
or log
e
k=log
e
A−
RT
E
a
or 2.303log
10
k=2.303log
10
A−
RT
E
a
For a first order reaction t
1/2
=
k
0.693
So, k=
600
0.693
sec
−1
(t
1/2
=10min=600sec)
=1.1×10
−3
sec
−1
Hence, log(1.1×10
−3
)=log(4×10
13
)−
2.303×8.314×T
98.6×10
3
T=310.95 K
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