Question

2 in bracket a b + c d bracket close minus A square minus b square + c square + b square factorise

Answer 1

=> 2(ab + cd) - a² - b² + c² + d²

=> 2ab + 2cd - a² - b² + c² + d²

=> -a² + 2ab - b² + c² + 2cd + d²

=> (-a² + 2ab - b²) + (c² + 2cd + d²)

=> -(a² -2ab + b²) + (c² + 2cd + d²)

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● USING ALGEBRAIC PROOERT :-

$= > { \alpha }^{2} - 2 \alpha \beta + { \beta }^{2} = {( \alpha - \beta )}^{2}$

◢AND

$= > { \alpha }^{2} + 2 \alpha \beta + { \beta }^{2} = {( \alpha + \beta )}^{2}$

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◢THEN

=> [-(a - b)² + (c + d)²]

=> [(c + d) ² - (a - b) ²] ________[Eq(1)]

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● WE KNOW THAT

$= > ( { \alpha }^{2} - { \beta }^{2} ) = ( \alpha + \beta )( \alpha - \beta )$
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● THEN, BY Eq(1)

=> [(c + d) + (a + b)].[(c + d) - (a + d)]

=> [c + d + a + b].[c + d - a - d]

=> -(a + b + c + d).(a + b - c - d)
____________________[◢ANSWER]

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☆$BE \: \: BRAINLY$☆

Answer 2

Answer:

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