Question

2. In fig 0 is the centre of the circle.If angle ABD=35°, find angle ACD. ​

Answer 1

Answer:

The answer for this question is 55°.

Step-by-step explanation:

angle DAB will be 90°

Hence,AngleADB will be =180-(Angle DAB+angleADB) (Angle sum property of triangle)

Hence ADB= 180-(90+35)

= 180-135

= 55°

Now, Angle ACB will be equal to angle ADB (angle in the same segments are equal )

Therefore Angle ACB will be 55°