Question

2.) In Fig. 10.11, if TP and TQ are the two tangents
to a circle with centre O so that Z POQ = 110°,
then Z PTQ is equal to
(A) 60°
(B) 700
(C) 80°
(D) 90°​

Answer 1

Answer:

70°

Step-by-step explanation:

because the quad. formed by centre, point of contact of two tamgents and ext pt. is a cyclic quad

so sum of opposite angles is 180°

Answer 2

Answer:

In quadrilateral OPTQ

110°+90°+90°+Angle PTQ= 360°

290°+ Angle PTA =360°

Angle PTQ =360°-290°

Angle PTQ= 70°

Option (b) is correct✅✅✅

=70°