2. In Fig. 10.37, AB || CD and I transversal which intersects AB and CD at E and F, respectively. If angle2 : angle 1 = 5: 4, find the measure of each of the angles.
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1
Answer:
We know that AB∥CD and t is a transversal
from the figure we know that ∠AEF and ∠EFD are alternate angles
So we get
∠AEF=∠EFD
Dividing both side by 2 we get
2
1
∠AEF=
2
1
∠EFD
So we get
∠PEF=∠EFQ
The alternate interior angles are formed only when the transversal EF cuts both FQ and EP
Therefore it is proved that EP∥FQ
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Answer:
10.37, AB || CD and I transversal which intersects AB and CD at E and F, respectively. If angle2 : angle 1 = 5: 4, find the measure of each of the angles.
Explanation:
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