Math, asked by brundag, 1 month ago

2. In Fig. 11.30, D and E are two points on BC such that BD = DE = EC. Show that ar(ABD)=ar (ADE) = ar (AEC).
Can you now answer the question that you have left in the "Introduction of this chapter, whether the field of Budhia has been actually divided into three parts of equal area?

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Answered by ashmitasoni13

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In the following figure, D and E are two points on BC such that BD = DE = EC. Show that ar (ABD) = ar (ADE) = ar (AEC). ... In the same way, by dividing BC into n equal parts and joining the points of division so obtained to the opposite vertex of BC, you can divide ΔABC into n triangles of equal areas.]

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Answered by brajamohanp21

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HII

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2. In Fig. 11.30, D and E are two points on BC such that BD = DE = EC. Show that ar(ABD)=ar (ADE) = ar (AEC). Can you now answer the question that you have left in the "Introduction of this chapter, whether the field of Budhia has been actually divided into three parts of equal area? ​

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2. In Fig. 11.30, D and E are two points on BC such that BD = DE = EC. Show that ar(ABD)=ar (ADE) = ar (AEC).
Can you now answer the question that you have left in the "Introduction of this chapter, whether the field of Budhia has been actually divided into three parts of equal area?