Question

2. In Fig. 13.23, AB = CD and AB || CD Prove that AABO ADCO. A O D B​

Answer 1

Answer:

GIVEN

AB= CDAB ll CD

To prove

\sf{ \triangle \: ABO ≅\: \triangle \: DCO}△ABO≅△DCO

Solution

consider ∆ ABO and ∆ DCO

AB= CD [ given]

angle BOA= angle DOC [ vertically opposite angles ] since AB ll CD

angle OBA = OCD [ vertically opposite angles] since AB ll CD

Therefore by AAS criteria ∆ ABO ≅ DCO