Question

2. In Fig. 8.13. find tan P-cot R.​

Answer 1

Answer:

0

Step-by-step explanation:

(PR)^2=(PQ)^2+(QR)^2

(13)^2=(12)^2+(QR)^2

169=144+(QR)^2

(QR)^2=169-144

(QR)^2=25=5cm

TanP=5/12

CotP=12/5

5/12-12/5 take LCM

5×12-12×5/60

60-60/60

0

HOPE IT'S HELPFUL FOR YOU....

Answer 2

Answer

Using pythagoras theorem,

(PR) ² = (PQ)² + (PR)²

⇒(QR)² = (13)² - (12)

=169 – 144 = 25

QR = 5 cm

tan p - cot r

= QR/PQ - QR/PQ

= 5/12 - 5/12

=0