Question

2. In figure 1.13 BC LAB, AD AB.
BC = 4, AD = 8, then find
AT A ABC)
AC A ADB)
D
Fig. 1.13​

Answer 1

Formulae for finding area of triangle is

$\frac{1}{2} \times b \times h$

But as 1/2 is common it would usually be cut

Also, b (base) of both triangles are the same i.e line AB.

So, base would to be cut, so only height is uncommon

So the height is written.