Question

2] In fiz, LABC = LA CB , AD is bisector
of LBAC and AD meets BC at D Prove
that , D is midpoint of bc​

Answer 1

Answer:

Here, we can see that ∠BAC is bisected by AD where AD touches BC at D. BC=BD+DCwhere, BC=3cm. We also have the values of adjacent sides AB=6cmand AC=5cm.

These satisfy the requirements of angle bisector theorem. Then, by the theorem, we have:

ABBD=ACDC

⇒DC=AC∗BDAB=5∗36=2.5cm

hope it helps

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