Biology, asked by anweshanandu45, 4 days ago

2.
In order to study and prove a particular physiological process in plants, the following
experiment was set-up. Study the same and then answer the question that follows:
B
с
D
SMT. SO
17
Soda lime
Lime water
Germinating Lime water
seeds

Answers

Answered by 7766872015
1

Answer:

(a) The experiment demonstrates that carbon dioxide is produced during the process of respiration in

germinating seeds.

(b) Soda lime is placed in bottle ‘A’ as it indicates the passage/presence of carbon dioxide in bottle

A. Another property of soda lime is that it absorbs carbon dioxide that is present in the air. The clear limewater in bottle B indicates that the air that enters the flask C is free from carbon dioxide.

(c) The bottle D holding limewater should indicate that carbon dioxide is produced as a result of respiration occurring in bottle ‘C’ possessing the germinating seeds. As carbon dioxide is produced in the bottle C, limewater turns milky that enters the bottle ‘D’.

(d) The chemical reaction is as written below:

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + 38 ATP (energy)

(e) The bottle ‘C’ is covered with a black cloth in order to restrict any chance of photosynthesis so as to make sure the process of respiration only is carried out and observed.

(f) A thermometer is inserted in bottle C to observe the changes in temperature. Respiration causes the temperature to rise, if there is no respiration, the temperature will not rise.

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