Math, asked by mona76592, 8 months ago

2. In parallelogram ABCD, angleB-angleA = 40°. Find all the anges
of parallelogram ABCD.​

Answers

Answered by jaswanthbabu36
1

Answer:

if the angleb-anglea=40

we know that angle a+angle b=180

sum of alternate angles are is 180

angle a=140 and angle b=40

angle a=angle c (opposite angles are equal)

angle b=angle d (opposite angles are equal)

angle a=140

angle c=140

angle b=40

angle d=40

Answered by Anonymous
0

Answer:

Angle B = 140 degree

Angle C = 40 degree

Angle D = 140 degree

Step-by-step explanation:

In quadrilateral ABCD,

Angle A = 40 degree (Given)

We know that, Opposite angles of Parallelogram are congruent.

Therefore, Angle A = Angle C

i.e. Angle A = Angle C = 40 degree

Now,

Angle B = 180 - Angle A --------- (Interior angles are supplementary)

Angle B = 180 - 40

Angle B = 140 degree

Opposite angles are congruent; Therefore,

Angle D = 140 degree

Therefore,

Angle A = 40 degree

Angle B = 140 degree

Angle C = 40 degree

Angle D = 140 degree

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