2. In parallelogram PQRS, angle Q = (4x - 5)º and
S = (3x + 10)". Calculate : angle Q and angle R.
3. In rhombus ABCD :
(i) if angleA = 74°; find angle B and angle C
(ii) if AD = 7.5 cm; find BC and CD.
4. In square PQRS :
(i) if PQ = 3x - 7 and QR = x + 3; find PS.
(ii) if PR = 5x and QS = 9x - 8. Find QS.
Answers
Answer:
Step-by-step explanation:
THE 2 ONE IS THE PIC
3 .
Given Information:-
In Rhombus ABCD, angle A = 74°
AD = 7.5 cm
To Find:-
Angle B and C Measurement.
Length of BC and CD.
_______________________...
1. Angle of B and C measurement:-
Here, Angle A = 74°
Hence, Angle B = 180° - Angle A
= 180° - 74°
= 106° (Angle B value)
Therefore, measurement of angle C:
= 180° - Angle B
= 180° - 106°
= 74° (Angle C value)
Hence,
Angle B = 106°
Angle C = 74°
______________________...
2. Length of BC and CD:-
Here, AD = 7.5 cm
As we know, in a Rhombus,
P=4S
(where P means Perimeter and S stands for sides)
Henceforth, BC = 7.5 cm
and also CD = 7.5 cm
REQUIRED ANSWER:-
Angle of B = 106 and of C = 74
.Length of BC and CD is 7.5 cm
4.
As it is a Square :
So,
*All the sides are equal ...
So,
3x-7=x+3
3x-x=7+3
2x=10
x=10/2
=>x = 5
Substituting:
x+3 = 5+3 = 8
PS = 8
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We know that the diagonals of a square are equal
Thus,
PR = QS
5x = 9x - 8
4x = 8
x = 2.
Now,
QS = 9x - 8 = 18 - 8 = 10.
Thus,
QS = 10.
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I HOPE U UNDERSTAND
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SARANGAE
Answer:
Step-by-step explanation:
2.angle q= angle s
4x-5=3x+10
x=15
angle q=55
angle r +angle q=180
angle r=125
3.i)angle a=angle c
angle c=74
angle a+angle b=180
angle b=106
ii)in rhombus all sides are equal
ad=bc=cd=7.5cm
4. in sqare all sides are equal