Question

2. In PQR , PQ. = PR. If LQ=48 ", then find LP and LR... please help​

Answer 1

Answer:

pqr = pr lp = lr

then equal

Step-by-step explanation:

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Answer 2

Answer:

( I denote angle as L )

In ΔPQR,

PQ = PR therfore,

L Q = L R ( equal opp. sides substents

equal angles )

\boxed{~L~R~=~48°~}

L R = 48°

L Q + L R + L P = 180°

48° + 48° + L P = 180°

\boxed{~L~P~=~84°~}

L P = 84°