2. In quadrilateral ABCD, AB = 40 cm, BC = 35 cm, CD = 48 cm.DA = 29 cm and BD = 29 cm. Find the area of quadrilateralABCD.
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Answer:
use heron's formula to do so
in triangle ABD
semi perimeter(s)=(29+29+40)/2=49
therefore,√(49-29)(49-29)(49-40)=60cm^2
In triangle BCD
semi perimeter(s)=(48+35+29)/2=56
therefore,√(56-48)(56-35)(56-29)=18√14
total area=60+18√14=78√14
=294.8492(approx.)
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