Question

2. In the adjoining figure, ABCD is a square. Find the
length of AE.
10 m
o
10m
14​

Answer 1

Answer:

DE=14+10

DE=24

it is a right angled traingle

so,

AE²=AD²+DE²

AE²=10²+24²

AE²=100+576

AE=√676

AE=26m

Answer 2

Answer:

Step-by-step explanation:

As ABCD is a square, that means ∠D is 90 degree

therefore, by Pythagoras theorem

AE²= AD²+DE²

AE² = (10)²+(10+14)²

AE²=(10)²+(24)²

AE²= 100+576

AE²=676

AE=√676

AE = 26

Hence proved

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