2. In the adjoining figure, ABCD is a square. Find the
length of AE.
10 m
o
10m
14
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Answered by
3
Answer:
DE=14+10
DE=24
it is a right angled traingle
so,
AE²=AD²+DE²
AE²=10²+24²
AE²=100+576
AE=√676
AE=26m
Answered by
3
Answer:
Step-by-step explanation:
As ABCD is a square, that means ∠D is 90 degree
therefore, by Pythagoras theorem
AE²= AD²+DE²
AE² = (10)²+(10+14)²
AE²=(10)²+(24)²
AE²= 100+576
AE²=676
AE=√676
AE = 26
Hence proved
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