Question

2. In the adjoining figure, AD-CF and CB - DE. Prove that
(a) AB is parallel to EF.
(b) AB EF​

Answer 1

Answer:

∆ACB is congruence to ∆FDE. (RHS)........1

Step-by-step explanation:

from equation 1 we get angle F = Angle A ( cpct)

now it is the alternative angle so it is said AB is parallel to EF

Answer 2

Answer:

Check your answer please