Question

(2) In the adjoining figure,
chord PQ and chord RS intersect
each other at point T.​

Answer 1

Answer:

Here is your solution... hope it helps...

Step-by-step explanation:

To Prove: ∠STQ = 1/2 [m(arc SQ) + m(arc PR)]

Construction: Draw seg PS.

Proof: ∠SPQ = 1/2 m(arc SQ) → (i) [inscribed angle theorem]

∠PSR = 1/2 m(arc PR) → (ii) [Inscribed angle theorem]

∠STQ is an exterior angle of ∆SPT.

∠STQ = ∠SPT + ∠PST [Remote interior angle theorem]

∠STQ = ∠SPQ + ∠PSR. [P - T - Q & S - T - R]

∠STQ = 1/2 m(arc SQ) + 1/2 m(arc PR) [ From (i) and (ii) ]

∠STQ = 1/2 [m(arc SQ) + m(arc PR) ]

HENCE PROVED...!

Mark me the brainliest !!

Hope it helps....