Question

2. In the adjoining figure, the diagonals AC and BD of parallelogram ABCD intersect at 0. If angleOBC = 36°, angleODC = 28° and angleAOD = 64°; find the measure of (i) angleOAD (ii) angleOCD.​

Answer 1

Answer: OAD= 58degree

Step-by-step explanation:

SIDES OF A PARALLELOGRAM ARE PARALLEl

OA=OD(DIAGONAL OF A PARALLELOGRAM BISECT EACH OTHER)

THUS

ANGLE OAD=ODA (ANGLES OPP. TO EQUAL SIDES )

so angle OAD + angle DOA+ ANGLE ODA =180

angle 2OAD+ 64°=180°

2OAD=180-64

2OAD=116

OAD,=116/2

OAD =58°

¡¡ OC=OD ( DIAGONAL OF A PARALLELOGRAM BISECT EACH OTHER)

THUS

ANGLE ODC=ANGLE OCD=28°(ANGLES OPP. TO EQUAL SIDES)