Question

2
In the arrangement shown in figure all surfaces are smooth. Select the correct altemativel(s)
(A) for any value of acceleration of A and B are equal
(B) contact force between the two blocks is zero only if
A =tano
mg
(C) contact force between the two blocks is zero for any value of m, or me
(D) normal reactions exerted by the wedge on the blocks are equal​

Answer 1

(A) for any value of the acceleration of A and B are equal.

Explanation:

• The first option asserts a true claim because it correctly states that 'the contact force lying between the blocks is zero due to the surfaces being smooth and having no friction.'
• Because the contact force between the blocks is zero, the motion of blocks is isolated and every block moves with an acceleration of gsinθ.
• The other statements assert a false claim as the contact force amongst the blocks is zero when there is no friction(makes second and third option false) while the last statement is false as the normal reactions displayed by wedge are not equal.

Learn more: acceleration

brainly.in/question/4276009

Answer 2

Answer:

a) and c)

Explanation:

let mass of A = M

let mass of B= m

the vertical force down the plane for first(A) is Mgsintheta so acceleration gsintheta

the vertical force down the plane for second(B) is mgsin theta so acceleration gsintheta

as we can observe acceleration is same for both so a option correct

Also if two bodies in contact are under free fall the normal reaction between them = 0 so c option also correct..

d option is not correct because for A the normal reaction by wedge is Mg cos theta and for B it is mgsintheta

Hope u got ur answer