2) In the fig alongside circles with centres X and Y touch each other at
point Z. A secant passing through Z intersects the circles at points A and B
respectively. Prove that Radius XA || Radius YB
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Answer: mark me brainliest
See figure attached
I hope it helps
Step-by-step explanation: Construction: Draw segments XZ and ..YZ........ .
Proof: By theorem of touching circles, points X, Z, Y are ..concyclic........ .
..∠ YZB ........vertically opposite angles
Let
..... (I)
Now, seg XA ≅seg XZ ........ (...radius of the same circle.......)
= ....∠ XZA...... = a ........ (isosceles triangle theorem) (II)
similarly, seg YB ≅ .YZ......... ........ (.radius of the same circle.........)
.∠ZBY......... = a ........ (.isosceles triangle theorem.........) (III)
∴from (I), (II), (III),
∠ XAZ = .∠ ZBY.........
∴radius XA || radius YB .......... (..since alternate interior angles are equal........)
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