Question

2. In the figure , BD = 8, DC = 12 and
B-D-C then AC A ABD): AC A ADC)=
8
D
C
12
O 1:2
O O
2:1
O
2:3
O
3:2​

Answer 1

Given :-

• BD = 8cm & DC = 12
• B - D - C

To Find :-

• The ratio of A(ΔABD) : A(ΔADC).

Solution :-

As we know that,

The ratio of the area of the two Δs is equal to the ratio of the product of their bases and their corresponding heights.

$↪\frac{A(ΔABD)}{A(ΔADC)} = \frac{b_1 × h_1}{b_2 × h_2}$

$↪\frac{A(ΔABD)}{A(ΔADC)} = \frac{BD × \cancel{AD}}{DC × \cancel{AD}}</h3><p>$

$↪\frac{A(ΔABD)}{A(ΔADC)} = \frac{BD}{DC}$

$↪\frac{A(ΔABD)}{A(ΔADC)} = \frac{ \cancel8}{ \cancel{12}}$

$↪\frac{A(ΔABD)}{A(ΔADC)} = \frac{2}{3}$

${ \boxed{ \red{A(ΔABD) : A(ΔADC) = 3:2}}}$