Question

2. In the figure, DE || BC if AE/AC =2/5 and AB = 15cm, then AD =?​

Answer 1

MARK IT AS BRAINLIEST

ANSWER

GIVEN : Δ ABC WITH BASE BC, DE II BC, AE / AC = 2 / 5, AB = 15 CM.

TO FIND : AD

PROOF: IN Δ ADE AND Δ ABC

                      ∠A = ∠A  ( COMMON )

                       ∠ADE = ∠ABC ( CORRESPONDING ANGLE )( DE II BC )

                           Δ ADE ≈ ΔABC ( AA CRITERIA )

                           

                              ∴ AD / AB = AE / AC ( CONVERSE OF BPT )

                                 AD / 15 = 2 / 5

                                    AD = 6 CM