2 In the figure, if AB || CD || EF, PQ || RS,
∠RQD = 25° and ∠CQP = 60°, then find ∠QRS.
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Step-by-step explanation:
Extended line PQ to intersect AB parallel to RS and mark the intersecting point as O and end point of the line as M.
QRO=RQD=25°( Alternative angles)
By construction,
AOQ=CQP=60° (Corresponding angled)
MOA+AOQ=180° (linear pair)
MOA=180°-60°=120°.
Again, MOA=ORS=120°.( corresponding angles)
QRS=QRO+ORS=120°+25°=145°.
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