(2) In the figure is the centre of the circle,
such that mL AOC = 140° then find
nd mLABC.
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Answer:
The answer is 110° .
Because, other∠AOC=360°-140°=220°
[We know that the center angle is twice the angle of the circle]
Hance, 2∠ABC=∠AOB
or, ∠ABC=1/2×220°=110°
hope it will help you...
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