Question

2. In the figure O is the centre of the circle. What is the measure of ACB

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Answer 1

Answer:

It will be 90°

(As we know the front angle formed at the center of a circle by an arc , is the double of the angle formed by the same arc at any point of the circle.It is a theorem)

<AOB =180°

So according to the theory the angle at the center of the circle which is <AOB is double of the angle formed by the same arc at any point of the circle.So <ACB = 180°/2

or, <ACB = 90°

ANOTHER PROCESS

As we know angle in a semi circle is a right angle so <ACB = 90° .

I hope that it will help you .