Question

2) In the first semester of B.Tech, a student is expected to take 6 subjects. The grades for each
subject can be S (10 points), A (9 points), B (8 points), C (7 points), D (6 points), E (5 points), F
(Fail). As per the rules, an enrolled student should obtain a minimum grade E in each subject to
get promoted to the next semester. What is the total number of possible ways in which a student
can get promoted?​

Answer 1

Answer:

46656

Step-by-step explanation:

for passing each subject one has 6 choices = S , A, B,C,D,E

so for 6 subject no of ways will be $6^{6}$ = 46656

Answer 2

Given :  A student is expected to take 6 subjects.

The grades for each  subject can be S (10 points), A (9 points), B (8 points), C (7 points), D (6 points), E (5 points), F  (Fail).

An enrolled student should obtain a minimum grade E in each subject to

get promoted to the next semester.

To Find :    total number of possible ways in which a student  can get promoted

Solution:

Total Subjects = 6

Total possible Grades = 7   ( S , A , B , C , D , E , F )

Possible Grades which are  required to promote = 6  ( S , A , B , C , D , E  )

In Each subject students can get one of the 6 possible grades to promote

Hence total possible ways

= 6 x 6 x6 x 6 x 6  x6

= 6⁶

= 46,656

46,656 total number of possible ways in which a student  can get promoted

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