Math, asked by sambasivam496, 9 hours ago

2. in the following fig QA PERPENDICULAR AB AND PB PERPENDICULAR AB THEN AQ IS ​

Answers

Answered by becyber
0

Answer:

In triangles AOQ and BOP, we have

       ∠OAQ=∠OBP           [Each equal to 90  

]

       ∠AOQ=∠BOP           [Vertically opposite angles]

Therefore, by AA-criterion of similarity

       △AOQ∼△BOP

⇒    

BO

AO

=  

OP

OQ

=  

BP

AQ

 

⇒      

BO

AO

=  

BP

AQ

 

⇒    

6

10

=  9

AQ

 

⇒    AQ=  6

10×9

=15cm

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