2. in the following fig QA PERPENDICULAR AB AND PB PERPENDICULAR AB THEN AQ IS
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Answer:
In triangles AOQ and BOP, we have
∠OAQ=∠OBP [Each equal to 90
∘
]
∠AOQ=∠BOP [Vertically opposite angles]
Therefore, by AA-criterion of similarity
△AOQ∼△BOP
⇒
BO
AO
=
OP
OQ
=
BP
AQ
⇒
BO
AO
=
BP
AQ
⇒
6
10
= 9
AQ
⇒ AQ= 6
10×9
=15cm
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