Question

2. In the given figure, ABCD is a quadrilateral-shaped field in
which diagonal BD is 36 m, AL 1 BD and CM I BD such that
AL 19 m and CM = 11 m. Find the area of the field.​

Answer 1

Step-by-step explanation:

The given details are,

AL⊥BD and CM⊥BD

AL=19 m,CM=11 m,BD=36m

By using the formula,

Area(quad. ABCD) =area(△ABD)+area(△ACD)

Also, area of triangle =1/2×base×height

∴Ar.(quad.ABCD)=(1/2×BD×AL)+(1/2×BD×CM)

=(1/2×36×19)+(1/2×36×11)

=342+198

=540 m

2