Question

2. In the given figure, ABCD is a rectangle whose diagonals AC and BD intersect at 0. If 20AB = 32°, find () ZACB (i) ZOBC D 32° A B​

Answer 1

Answer:

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Step-by-step explanation:

R.E.F image

∠CAB=∠DCA (alternate)

=27

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and ∠ACB=90

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−27

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=63

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∠CBO=90

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∴∠CBO=90−63=27

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Answer 2

Step-by-step explanation:

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