Question

2. In the given figure, ABCD is a rectangle whose diagonals AC and BD intersect at O. If angle OAB = 32°, find (1) angle ACB (ii) angle OBC​

Answer 1

Answer:

We know that the diagonals of rectangle are equal and bisect each other.

∴ OA = OB

⇒ ∠OAB = ∠OBA = 28°

Also, each angle of rectangle measures 90°

∴ ∠ABC = 90°

∠OBA + ∠OBC = 90°

⇒ 32° + ∠OBC = 90°

∴ ∠OBC = 58°

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Answer 2

Step-by-step explanation:

given angle OAB =32

SO OAB=OBA=32 (OPPOSITE ANGLE ARE EQUAL)

TO FIND ACB

ANGLE A=C (OPPOSITE ANGLE ARE EQUAL)=32

TO FIND OBC

(SUPPLIMENTORY ANGLES)

18O - 32 =148