Math, asked by wilsondsouza912, 4 months ago

2) In the given figure, ABCD is a rhombus, such that ∆ACB = 50°
Find the measure of ∆ADB.

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Answers

Answered by Anonymous
4

Answer:

ACB=50

o

,∠ACB=∠CAD(∵BC∣∣AD)

In △AOD,∠DAO+∠ADO+∠AOD=180

o

50+∠ADB+90

o

=180

o

∠ADB=180

o

−140

o

=40

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