2) In the given figure, ABCD is a rhombus, such that ∆ACB = 50°
Find the measure of ∆ADB.
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Answer:
ACB=50
o
,∠ACB=∠CAD(∵BC∣∣AD)
In △AOD,∠DAO+∠ADO+∠AOD=180
o
50+∠ADB+90
o
=180
o
∠ADB=180
o
−140
o
=40
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