Question

2) In the given figure, ABCD is a rhombus, such that ∆ACB = 50°
Find the measure of ∆ADB.

​

Answer 1

Answer:

ACB=50

o

,∠ACB=∠CAD(∵BC∣∣AD)

In △AOD,∠DAO+∠ADO+∠AOD=180

o

50+∠ADB+90

o

=180

o

∠ADB=180

o

−140

o

=40