2. In the given figure, BC = CA and ∠A = 40°. Then, find ∠ACD
Answers
Answered by
6
Answer:
Exterior angle is equal to sum of opposite interior angles
∠ACD = ∠A + ∠B
As ΔACB is isosceles triangle with AC = BC
Then ∠A must be equal to ∠B
∴ ∠ACD = 40° + 40° = 80°
Similar questions