Question

2. In the given figure, BO and CO are the bisectors of the exterior angles meeting each
other at O. If A = 70° find BOC.


please answer in full and fast​

Answer 1

ANSWER
∵sumofanglesonastraightline=180
∘

=>∠ABC=180
∘
−2θ
and∠ACB=180
∘
−2α
In△ABC
=>∠A+∠ABC+∠ACB=180
∘

=>70
∘
+180−2θ+180−2α=180
=>250
∘
−(2θ+2α)=0
=>2(θ+α)=250
∘

=>θ+α=125
∘
−(1)
In△BOC
=>∠CBO+∠BCO+∠BOC=180
∘

=>θ+α+∠BOC=180
∘

=>125
∘
+∠BOC=180
∘
−from(1)
∴∠BOC=55
∘




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