Question

2. In the given Figure, find the measures of ZPRQ and ZPRT.​

Answer 1

Answer:-

= <P + <Q + <R = 180⁰

= 60⁰+55⁰+<R = 180⁰

= 115⁰+<R = 180⁰

= <R = 180⁰-115⁰

•°• <R = 65⁰

Again

= <PRQ + <PRT = 180⁰

= 65⁰+ <PRT = 180⁰

•°• <PRT = 180⁰-65⁰

= 115⁰

Answer 2

$answer$

Answer:-

Answer:- = <P + <Q + <R = 180⁰

Answer:- = <P + <Q + <R = 180⁰= 60⁰+55⁰+<R = 180⁰

Answer:- = <P + <Q + <R = 180⁰= 60⁰+55⁰+<R = 180⁰= 115⁰+<R = 180⁰

Answer:- = <P + <Q + <R = 180⁰= 60⁰+55⁰+<R = 180⁰= 115⁰+<R = 180⁰= <R = 180⁰-115⁰

Answer:- = <P + <Q + <R = 180⁰= 60⁰+55⁰+<R = 180⁰= 115⁰+<R = 180⁰= <R = 180⁰-115⁰•°• <R = 65⁰

Answer:- = <P + <Q + <R = 180⁰= 60⁰+55⁰+<R = 180⁰= 115⁰+<R = 180⁰= <R = 180⁰-115⁰•°• <R = 65⁰Again

Answer:- = <P + <Q + <R = 180⁰= 60⁰+55⁰+<R = 180⁰= 115⁰+<R = 180⁰= <R = 180⁰-115⁰•°• <R = 65⁰Again= <PRQ + <PRT = 180⁰

Answer:- = <P + <Q + <R = 180⁰= 60⁰+55⁰+<R = 180⁰= 115⁰+<R = 180⁰= <R = 180⁰-115⁰•°• <R = 65⁰Again= <PRQ + <PRT = 180⁰= 65⁰+ <PRT = 180⁰

Answer:- = <P + <Q + <R = 180⁰= 60⁰+55⁰+<R = 180⁰= 115⁰+<R = 180⁰= <R = 180⁰-115⁰•°• <R = 65⁰Again= <PRQ + <PRT = 180⁰= 65⁰+ <PRT = 180⁰•°• <PRT = 180⁰-65⁰

Answer:- = <P + <Q + <R = 180⁰= 60⁰+55⁰+<R = 180⁰= 115⁰+<R = 180⁰= <R = 180⁰-115⁰•°• <R = 65⁰Again= <PRQ + <PRT = 180⁰= 65⁰+ <PRT = 180⁰•°• <PRT = 180⁰-65⁰ = 115⁰