Question

2
. In the given figure, if AD=CD = BC and
ZBCF =96, then ZDBC =
F
C696°
A А
+E
D
B​

Answer 1

Answer:

Given AD=CD=$$BC,

∴∠CAD=∠DCA and ∠CDB=∠CBD

By Exterior angle property 2x=y ……..(1)

in ΔBCD, 180−2y=∠BCD

and also 96+180−2y+x=180

96+180−4x+x=180

⇒x=32, substituting in (1) y=64=∠DBC.