2)
In the given figure, if AD is the median of triangle ABC then angle BAD is
a) 35°
c) 70
d) 55°
b) 110
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angle ABC = 35°
angle ABC = angle ACB [ AB= BC]
angle ACB = 35°
↓
angle ABC+ angle ACB + angle BAC=180°
→ 35°+35° + angle BAC = 180°
→ 70° + angle BAC = 180°
→ angle BAC = 180°-70°
→ angle BAC = 110°
★ D is the middle point of BC.
So,
angle BAD = angle BAC /2
= 110°/2
= 55°
So, angle BAD = 55°
Ans→ d)55°
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