2. In the given figure, the measure of BAC is 6 cm 2x + 20° 5 cm B 50 5 cm С la) 60 (c) 70 (b)50 (d) 80
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ABC and
A'B'C',
AB= A'B' (Given)
∠B = ∠B'(Given)
BC = B'C' (Given)
Hence, by S.A.S. theorem,
ABC
A'B'C'
Therefore,
By c.p.c.t
∠A = ∠A'
3x = 2x +20
x = 20°
Therefore angle A' = 2x +20
= 60°
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