2. In the given figure, ZABD = 3 ZDAB and ZADC = 120°.
Find the angles of AABD.
А
120°
C с
В.
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Answer
ABCD is a cyclic quadrilateral. we have
∠ABC+∠ADC=180
o
∠ABC=180
o
−120
o
=60
o
Also ∠ACB=90
o
( angle on a semi circle )
In ΔABC we have
∠BAC+∠ACB+∠ABC=180
o
∠BAC+90
o
+60
o
=180
o
∠BAC=180
o
−150
o
=30
o
ABCD is a cyclic quadrilateral. we have
∠ABC+∠ADC=180
o
∠ABC=180
o
−120
o
=60
o
Also ∠ACB=90
o
( angle on a semi circle )
In ΔABC we have
∠BAC+∠ACB+∠ABC=180
o
∠BAC+90
o
+60
o
=180
o
∠BAC=180
o
−150
o
=30
o
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