Question

2 In the given figure, ZBAD = 65° LABD = 70
ZBDC = 45
(i) Prove that AC is a
diameter of the
circle.
85
(ii) Find ZACB,
А
B
121 please answer as possible as ​

Answer 1

Answer:

Hi

Step-by-step explanation:

Given

BAD = 65˚

ABD = 70˚

BDC = 45˚

(i) In ABD,

BAD + ABD + ADB

= 180˚

65˚ + 70˚ + ADB = 180˚ {Sum of three angles of a}

ADB = 180˚ – (65˚ + 70˚)

= 45˚

ADC = ADB + BDC

45˚ + 45˚ = 90˚

AC is the diameter of the circle.

[Angle in a semi circle is 90˚] Proved

(ii) ACB = ADB = 45˚

{Angles in the same segment of a circle}.

Please Mark This Answer As Brainlist

Have A Nice Day