Question

2. In traingle PQR, PQ = PR, QR is extended to S and
angle PRS = 110°. Then, angle PQR =
A. 30° B. 50° C. 80° D. 70°

3. In traingle ABC and traingle DEF, AB = DE, BC = EF and
angle B = angle E. If the perimeter of traingle ABC is 20,
then the perimeter of traingle DEF is
A. 10 B. 20 C. 15 D. 40


4. In traingle ABC and traingle PQR, AB = PQ, angle A = angle P and angle B = angle Q. If angle A + angle C = 130°, then
angle Q= .....
A. 65° B. 130° C. 50° D. 1000

5. In traingle PQR , angle P = angle Q= angle R. If PQ = 6, then the
perimeter of traingle PQR is
A. 12 B. 9 C. 18 D. 24​

Answer 1

Answer:

here's your answers

1. a
2. c
3. b
4. a

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Answer 2

Answer:

Step-by-step explanation

3)In △ABC and △DEF

∠B=∠E (given)

∠C=∠F (Given)

∠A=∠D (third angle)  

Thus, △ABC∼△DEF (AAA rule)

Given, AB=3DE Since, AB



=DE

The two triangles are similar but not congruent.

4)In ABC,

Angle A + Angle C = 130 degree

As we know that sum of interior angles of triangle is 180 degree

so, angle A + angle B + angle C = 180 degree

[ angle A + angle C = 130 degree ]

130 degree + angle B = 180 degree

angle B = 50 degree

angle B = angle Q

so, angle Q = 50 degree