Question

2. In TraingleABC, AngleB = angleC. If AD, the bisector of AngleA meets BC at D, prove that AD is
perpendicular to BC.

Please answer!! Plz plz only answer

Answer 1

bro mujhe lagta hai ki isme ASA ka rule use hoga bcuz (1) angle B = C (2) AB = AC

(3) angle BAD = DAC

Thus trangle BAD & CAD sarwangsam honge

or AD,BC par perpendicular hoga

Answer 2

AB=AC (ANGLE B=ANGLE C ) (opposite sides are equal of two equal opposite angles)--(1)

Now in triangle ABD and triangle ACD

AB=AC(By 1)

Angle BAD=Angle CAD(Given)

Angle B =Angle C(Given)

triangel ABD us congruent to trianle ACD (BY ASA Rule)

Angle BDA= Angle CDA(By CPCT)

Angle BDA+Angle CDA =180 degree

X+X=180

2X=180

X=180/2

X=90 degree

Angle BDA and Angle CDA =90

AD is prependicular to BC