Question

2. In triangle ABC, AD is the perpendicular bisector of BC
(see Fig. 7.30). Show that triangle ABC is an isosceles
triangle in which AB=AC.


Hey mate help me
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Answer 1

In ∆ABD and ∆ADC

AD=AD..........COMMON SIDE

ADB=ADC.........EACH 90°

BD=DC.........AD IS BISECTOR

Therefore triangles are congruent

By c.s.c.t

AB=AC

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Answer 2

Answer:

AB/BD = Ac/Dc ( by bpt)

AB/Bc/2 = Ac /Bc/2 ( Bc is perpendicular bisector of AD )

so AB/ AD = AC/AD

here demonetors are same automatically AB = AC

hence it proved