Question

2. Inside a certain automobile engine,
the volume of air in a cylinder is
0.375 dm', when the pressure is 1.05
atm. When the gas is compressed to
a volume of 0.125 dm' at the same
temperature, what is the pressure of
the compressed air?​

Answer 1

Answer:

V1 = 0.375 dm3

V2 = 0.125

P1 = 1.05 atm

P2 = ?

'T' - Constant

P1V1 = P2V2

P2 = 3.8 dm3

Answer 2

Given : P1 = 1.05 atm

V1 = 0.375 dm³

V2 = 0.125 dm³

Find : P2= ?

Solution:

According to Boyle's law,

P1V1 = P2V2

1.05×0.375 = P2× 0.125

P2 = 1.05×0.375 ÷ 0.125

P2 = 1.05 × 3

P2 = 3.15 atm

Therefore, the pressure of the compressed air is 3.15 atm