Question

2 into 10 raise to -3

Answer 1

Step-by-step explanation:

You mean

$(2\times10)^{-3} \;\;0r\;\;\;2\times10^{-3}$

don't worry, let's find both:)

firstly

$(2\times10)^{-3}=20^{-3}=\frac{1}{20^{3}}=\frac{1}{8000}=0.000125$

Now, next

$2\times10^{-3}=2\times\frac{1}{10^{3}}=2\times\frac{1}{1000}=\frac{2}{1000}=0.002$

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