Math, asked by pompa85, 1 year ago

√2 is a zero of p(x)=6x³+√2x²-10x-4√2. Find other two zeros.​

Answers

Answered by HunterPettigrew1982
0

Answer:

Given that √2 is a zero of the cubic polynomial 6x3 + √2 x2 – 10x – 4 √2 , find its other two zeroes. +1 vote. 27 views ... p(x) = 6x3 + √2x2 - 10x - 4 √2. since x = √2 is a ... Basic (20 points). Two zeros are -2√2/3 and -√2/2 ...

Step-by-step explanation:

Answered by simranjitsingh7797
0

Answer:

Step-by-step explanation:

p(x) = 6x3 +  √2x2  - 10x - 4 √2

since x = √2 is a zero of p(x)  

⇒ (x - √2) will be a factor of  p(x)  

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