Question

-√2 is a zero of the polynomial p(X)=x^3-2x?why?​

Answer 1

Answer:

sorry

Step-by-step explanation:

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Answer 2

$if \: \: x \: = \sqrt{2} \: \: then \\ p( \sqrt{2} ) = {( \sqrt{2} )}^{3} - 2 \sqrt{2} \\ = 2 \sqrt{2} - 2 \sqrt{2} \\ = 0$

So, Root 2 is a zero of P(x).