Question

2 is a zero of x³-6x²+px-6 then the value of p is

Answer 1

Step-by-step explanation:

=> x³ - 6x² + px - 6 = 0

=> (2)³ - 6*(2)² + p(2) - 6 = 0

=> 8 - 24 + 2p - 6 = 0

=> -22 + 2p = 0

=> 2p = 22

=> p = 11

Answer 2

Answer:

p(2)=   p = 11

Step-by-step explanation:

p(x)=  $x^{3$-6$x^{2}$+px-6=0                              [x=0 as 2 is the zero of polynomial]

p(2)=   $2^{3} -6(2)^{2} +(p*2)-6$ = 0

p(2)=   $8 - (6*4) + (p*2) - 6$ = 0

p(2)=   $-22 + (p*2)$ = 0

p(2)=   p*2 = 22

p(2)=   p = 22/2

p(2)=   p = 11