Question

2 is added to twice a certain number and the
sum is doubled. The result is 10 less than 5 times
the original number. Find the original number.​

Answer 1

Answer:

Answer is 4

Step-by-step explanation:

Lets take the unknown no. as 'x'

So, the expression is

2 + x

But then the sum i.e x is doubled..so it is..

2+ 2x =5x -10

Transfer -10 with 2 and 2x with 5x

When we transfer..the sign changes..

So it is

2+10 = 5x-2x

12 = 3x

x = 12/3 = 4

According to me this is the answer..i suggest u to check it with someone..hope it helps..plz mark the brainliest if it does..

Thanks...Hv a good day :D

Answer 2

Given :

• 2 is added to twice a certain number and the

sum is doubled.

• The result is 10 less than 5 times the original number.

To find :

• Original number

Solution :

Let the original number be x

According to the question,

→ 2(2 × (Original number) + 2) = (5 × Original number) - 10

→ 2(2 × x + 2) = (5 × x) - 10

→ 2(2x + 2) = 5x - 10

→ 4x + 4 = 5x - 10

→ 4x - 5x = - 10 - 4

→ - x = - 14

→ x = 14

→ x = 14

→ The value of x = 14

Therefore, the original number is 14

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

Let's verify :-

To verify the value of the original number. Substitute the value of x in 2(2x + 2) = 5x - 10

If the LHS will be equal to RHS the. the value is right.

→ Taking LHS :-

→ 2(2x + 2)

→ 4x + 4

→ 4(14) + 4

→ 56 + 4

→ 60

LHS = 60

→ Taking RHS :-

→ 5x - 10

→ 5(14) - 10

→ 70 - 10

→ 60

→ RHS = 60

LHS = RHS

Hence, verified!