Question

2. Is it possible to construct a A ABC in which AB = 6 cm, angle A = 105º and angle B = 80° ? if not why​

Answer 1

Answer:

Step-by-step explanation:

No , we can not construct a triangle ABC in which angle B = 105°,angle C = 90° and AB+BC+AC =10cm

Answer 2

Answer:

In given figure , PQ=RS and ∠ORS=48

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In given figure O is the center of circle and point P,Q,R and S on the circumference of circle

Then line OP, OQ ,OR and OS are the radius of circle

So OP=OQ=OR=OS

In ΔOPQ and ΔORS

PQ=RS (Given )

OP=OR (Radius of circle)

OQ=OS (Radius of circle)

∴ΔPOQ≅ΔORS

∠ORS=∠OPQ=48

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Given ∠ORS=48

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OR=OS (radius)

∴∠OSR=∠ORS=48

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Given\angle ORS=48^{0}$$

In ΔORS

∠ROS+∠ORS+∠OSR=180

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⇒∠ROS+48+48=180

⇒∠ROS=180−48−48=84

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∠OPQ=48

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,∠ROS=84

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